[破碎的状态] BZOJ 1503 郁闷的出纳员
一道treap的喜闻乐见的题目
据说这题还能再用Splay AC一次呢
不管了先把treap的模版带上来..
treap我还是记得的只不过delete_node的时候出了点"小小"的问题
导致我WA了2次
#include<set>
#include<map>
#include<list>
#include<queue>
#include<stack>
#include<math.h>
#include<string>
#include<time.h>
#include<bitset>
#include<vector>
#include<memory>
#include<utility>
#include<stdio.h>
#include<sstream>
#include<fstream>
#include<iostream>
#include<stdlib.h>
#include<string.h>
#include<algorithm>
using namespace std;
struct node
{
int size;
int weight;
int val;
node * ch[2];
};
node * root;
node * null;
node * new_node(int x)
{
static node a[100005];
static int top=0;
node * t=&a[top++];
t->size=1;
t->weight=rand();
t->val=x;
t->ch[0]=null;
t->ch[1]=null;
return t;
}
void rotate(node * &x,int c)
{
node * y=x->ch[c];
x->ch[c]=y->ch[!c];
y->ch[!c]=x;
y->size=x->size;
x->size=x->ch[0]->size+x->ch[1]->size+1;
x=y;
}
void insert_node(node * &x,node * y)
{
if (x==null)
{
x=y;
return;
}
x->size++;
int c;
if (y->val>x->val)
{
c=1;
}
else
{
c=0;
}
insert_node(x->ch[c],y);
if (x->ch[c]->weight>x->weight)
{
rotate(x,c);
}
}
void delete_node(node * &x)
{
x->size--;
if (x->ch[0]==null)
{
if (x->ch[1]==null)
{
x=null;
return;
}
rotate(x,1);
delete_node(x->ch[0]);
}
else
{
delete_node(x->ch[0]);
}
}
int find_kth(node * x,int k)
{
if (k==x->ch[0]->size+1)
{
return x->val;
}
else if (k<=x->ch[0]->size)
{
return find_kth(x->ch[0],k);
}
else
{
return find_kth(x->ch[1],k-x->ch[0]->size-1);
}
}
int main()
{
#ifdef absi2011
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
#endif
null=new_node(0);
null->size=0;
null->weight=-1;
null->ch[0]=null;
null->ch[1]=null;
root=null;
int n,m;
scanf("%d%d",&n,&m);
int i;
int sum=0;
int tot=0;
int ans=0;
for (i=0;i<n;i++)
{
static char a[5];
scanf("%s",a);
if (a[0]=='I')
{
int x;
scanf("%d",&x);
if (x<m) continue;
x-=sum;
insert_node(root,new_node(x));
tot++;
}
else if (a[0]=='A')
{
int x;
scanf("%d",&x);
sum+=x;
}
else if (a[0]=='S')
{
int x;
scanf("%d",&x);
sum-=x;
for (;;)
{
if (tot==0) break;
if (find_kth(root,1)+sum<m)
{
delete_node(root);
tot--;
ans++;
}
else
{
break;
}
}
}
else
{
int k;
scanf("%d",&k);
if (k<=tot)
{
printf("%d\n",find_kth(root,tot-k+1)+sum);
}
else
{
printf("-1\n");
}
}
}
printf("%d\n",ans);
return 0;
}
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