100506 I 解题报告
最近我在写非人类题目啊...
链接:http://codeforces.com/gym/100506/attachments/download/2760/20142015-ct-s02e06-codeforces-trainings-season-2-episode-6-en.pdf
题意:
给出若干个ACM队的成绩,求排名
特殊规则:
如果罚时都相同,那么考虑最大的X,使得两者可以得分情况不同(做出题目数或者罚时不同)
如果再相同那只好相同了...
解法:没啥好说的,暴力去
代码:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 | # include < set > # include <map> # include <list> # include <queue> # include <stack> # include <string> # include <time.h> # include <math.h> # include <memory> # include <vector> # include <bitset> # include <fstream> # include <stdio.h> # include <utility> # include <sstream> # include <string.h> # include <iostream> # include <stdlib.h> # include <algorithm> using namespace std; struct team { string name; int ac[ 15 ]; int unac[ 15 ]; int ac_problems; int sum_time; friend bool operator < ( const team &a, const team &b) { if (a.ac_problems!=b.ac_problems) { return a.ac_problems>b.ac_problems; } else if (a.sum_time!=b.sum_time) { return a.sum_time<b.sum_time; } else { int i; int aa= 9 ,bb= 9 ; int unsolved_a= 0 ; int unsolved_b= 0 ; int unget_time_a= 0 ; int unget_time_b= 0 ; for (i= 300 ;i>= 1 ;i--) { for (;aa>= 0 ;) { if (a.ac[aa]>i) { unsolved_a++; unget_time_a+=a.ac[aa]; unget_time_a-=a.unac[aa]* 20 ; aa--; } else { break ; } } for (;bb>= 0 ;) { if (b.ac[bb]>i) { unsolved_b++; unget_time_b+=b.ac[bb]; unget_time_b-=b.unac[bb]* 20 ; bb--; } else { break ; } } if (unsolved_a!=unsolved_b) { return unsolved_a<unsolved_b; } else if (unget_time_a!=unget_time_b) { return unget_time_a>unget_time_b; } } } return a.name<b.name; } friend bool operator > ( const team &a, const team &b) { if (a.ac_problems!=b.ac_problems) { return a.ac_problems<b.ac_problems; } else if (a.sum_time!=b.sum_time) { return a.sum_time>b.sum_time; } else { int i; int aa= 9 ,bb= 9 ; int unsolved_a= 0 ; int unsolved_b= 0 ; int unget_time_a= 0 ; int unget_time_b= 0 ; for (i= 300 ;i>= 1 ;i--) { for (;aa>= 0 ;) { if (a.ac[aa]>i) { unsolved_a++; unget_time_a+=a.ac[aa]; unget_time_a-=a.unac[aa]* 20 ; aa--; } else { break ; } } for (;bb>= 0 ;) { if (b.ac[bb]>i) { unsolved_b++; unget_time_b+=b.ac[bb]; unget_time_b-=b.unac[bb]* 20 ; bb--; } else { break ; } } if (unsolved_a!=unsolved_b) { return unsolved_a>unsolved_b; } else if (unget_time_a!=unget_time_b) { return unget_time_a<unget_time_b; } } } return false ; } void clear() { memset(ac, 0 ,sizeof(ac)); memset(unac, 0 ,sizeof(unac)); ac_problems= 0 ; name= "" ; sum_time= 0 ; } void calc() { int i,j; for (i= 0 ;i< 10 ;i++) { for (j=i;j< 10 ;j++) { if (ac[i]>ac[j]) { swap(ac[i],ac[j]); swap(unac[i],unac[j]); } } } } }; team a[ 105 ]; map<string, int > ma; int main() { #ifdef absi2011 freopen( "input.txt" , "r" ,stdin); freopen( "output.txt" , "w" ,stdout); #endif ios::sync_with_stdio( false ); int t; cin>>t; int zu; for (zu= 0 ;zu<t;zu++) { ma.clear(); int n,m; cin>>n>>m; int i; for (i= 0 ;i<n;i++) { a[i].clear(); cin>>a[i].name; ma[a[i].name]=i; } for (i= 0 ;i<m;i++) { int time; string name; cin>>time; cin>>name; char prob; cin>>prob; string state; cin>>state; if (state== "rejected" ) { if (a[ma[name]].ac[prob- 'A' ]>= 1 ) continue ; a[ma[name]].unac[prob- 'A' ]--; } else { if (a[ma[name]].ac[prob- 'A' ]>= 1 ) continue ; a[ma[name]].sum_time-= 20 *a[ma[name]].unac[prob- 'A' ]; a[ma[name]].sum_time+=time; a[ma[name]].ac[prob- 'A' ]=time; a[ma[name]].ac_problems++; } } for (i= 0 ;i<n;i++) { a[i].calc(); } sort(a,a+n); int rank= 1 ; for (i= 0 ;i<n;i++) { if ((i== 0 )||(a[i]>a[i- 1 ])) { rank=i+ 1 ; } printf( "%d %s %d %d\n" ,rank,a[i].name.c_str(),a[i].ac_problems,a[i].sum_time); } } return 0 ; } |